i revised it a little more...
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <windows.h>
#include <conio.h>
int main (void)
{
char response[10];
int n=0;
int n2=0;
int picknum=0;
int picks[20];
int randomnumbers[20];
int correct=0;
float bet=0;
float winnings=100;
srand(time(NULL)); //Seed the random nubmer generator
do{
n=0;
n2=0;
correct=0;
printf("How many numbers do you want to pick? (1-20)\n \n \t - ");
scanf("%d", &picknum);
if(picknum>20) picknum=20;
if(picknum<1) picknum=1;
Beep(600, 100);
system("CLS");
do{
printf("What is your bet? You have %f credits\n \n \t - ", winnings);
scanf("%f", &bet);
Beep(600, 100);
system("CLS");
printf("Type the numbers you want to pick. After every number, hit enter.\n Repeat as nessissary.\n \n");
}while(bet>winnings);
while(n<picknum)
{
scanf("%d", picks+n);
if(picks[n]<80&&picks[n]>0) n++;
}
n=0;
while(n<20)
{
int test=rand()%80+1;
while(n2<n) //Check every value to make sure it isn't a duplicate
{
if(test==randomnumbers[n2]) break;
n2++;
}
if(n2==n)//If the while loop didn't break, they would be equal
{
randomnumbers[n]=test;
n++;
}
n2=0;
}
n=0;
n2=0;
while(n<picknum)
{
while(n2<20)
{
if(picks[n]==randomnumbers[n2]) correct++;
n2++;
}
n2=0;
n++;
}
//Don't know the scoring formula. Paste it here.
winnings+=((picknum*bet*correct)/10);
printf("You had %i correct. Your current number of credits is %f. Continue?(Y/N)\n \n \t - ", correct, winnings);
scanf("%s", response);
Beep(600, 100);
system("CLS");
if(response[0]=='N' || response[0]=='n') break;
}while(winnings>0);
printf("You have won %i credits", winnings);
}
is there any way to make it so that you wont win any money and will lose your bet if you dont get enough numbers right???
matt wuz here
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